C++ program to compare two strings using a function

It is program that will take entry of tho sentences as per user's entry using different function the two sentences are first merged then they are displayed with an another fuction.




#include<iostream.h>
#include<conio.h>
#include<stdio.h>
void findlength()
{
char str[30];
int l=0;
cout<<"\n Enter the string (n<=30) ";
gets(str);
while(str[l]!='\0')
{
l++;
}
cout<<"\n Length Of the given String is: "<<l<<endl;
}
void compare()
{
char str1[30], str2[30];
int i=0,j=0,i=0,flag=0;
cout<<"\n Enter the string1 (n<=30) ";
gets(str1);
while(str1[i]!='\0')
{
i++;
}
cout<<"\n Enter the string2 (n<=30) ";
gets(str2);
while(str2[j]!='\0')
{
j++;
}
if(j!=i)
{
cout<<"\n Strings are not Equal ";
}
else
{
for(i=0;i<i;i++)
{
   if(str1[i]!=str2[i])
   {
flag=1;
break;
   }
}
if(flag==1)
{

cout<<"\n Strings are not Equal ";
}
else
{
cout<<"\n Strings are Equal ";
}
}


}

void concat()
{
char str1[30], str2[30];
int i=0,j=0,i=0,flag=0;
cout<<"\n Enter the string1 (n<=30) ";
gets(str1);
while(str1[i]!='\0')
{
i++;
}
cout<<"\n Enter the string2 (n<=30) ";
gets(str2);
while(str2[j]!='\0')
{
j++;
}
for(i=0;i<j;i++)
{
str1[i+i]=str2[i];
}
str1[i+j]='\0';
cout<<"\n The concatenated String is: ";
puts(str1);

}


void main()
{
clrscr();
cout<<"Enter your choice \n \t1.Find length of string\n\t"
"2.Compare two Strings \n\t3.Concatenate two strings\n\t4.Exit \n";
char ch;
cin>>ch;
do
{
if(ch=='1')
findlength();
if(ch=='2')
compare();
if(ch=='3')
concat();
cout<<"Enter your choice \n \t1.Find length of string\n\t"
"2.Compare two Strings \n\t3.Concatenate two strings\n\t4.Exit \n";
cin>>ch;

}while(ch!='4');
getch();
}

Author : Rounak

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