C++ Program to generate report card of a student as per entry of marks

This C++ based program basically will take enrty of a students name, roll number and his/her marks in atleast 3 subjects and generate a report card of that students performance. This program has been desinged using arrays. This program undertakes multiple cases so switch cases has been used to simplify it. This program has also undertaken the concept of strings with the header file <string.h> this will help in enhancing a students mind that how well can three arrays be used to generate a new array. The program is as follows:
#include<iostream.h>
#include<conio.h>
#include<stdio.h>
#include<string.h>

void main()
{
clrscr();
char *name[50],*nm;
int rno[50],m1[50],m2[50],m3[50],tot[50],i,n,trn;
cout<<"Enter no. of records: ";
cin>>n;
for(i=0;i<n;i++)
{
cout<<"Enter Name of Student "<<i<<": ";
gets(name[i]);
cout<<"Enter Roll No. of Student "<<i<<": ";
cin>>rno[i];
cout<<"Enter Mark1 of Student "<<i<<": ";
cin>>(m1[i]);
cout<<"Enter Mark2 of Student "<<i<<": ";
cin>>(m2[i]);
cout<<"Enter Mark3 of Student "<<i<<": ";
cin>>(m3[i]);
tot[i]=m1[i]+m2[i]+m3[i];
}
char ch,ch1;
int flag=0;
cout<<"\n\t1.Report card for particular student"
"\n\t2.List all records\n\t3.Exit";
cin>>ch;
do
{
switch(ch)
{
case '1':
cout<<"\nEnter the Roll no.";
cin>>trn;
flag=0;
for(i=0;i<n;i++)
if(trn==rno[i])
{
cout<<"\n Name: "<<name[i]<<"\t";
cout<<"Roll No.: "<<rno[i];
cout<<"\nMark1: "<<m1[i];
cout<<"\nMark2: "<<m2[i];
cout<<"\nMark3: "<<m3[i];
cout<<"\n----------";
cout<<"\nTotal: "<<tot[i];
flag=1;

}
if(flag==0)
cout<<"Record not found";
break;
case '2':
cout<<"\nRollno\tName     \tMark1\tMark2\tMark3";
cout<<"\tTotal";
cout<<"\n------\t----------\t----\t----\t----";
cout<<"\t-----";
for(i=0;i<n;i++)
{
cout<<"\n"<<rno[i]<<"\t"<<name[i]<<"\t"
<<m1[i]<<"\t"<<m2[i]<<"\t"<<m3[i]<<"\t"
<<tot[i];
}
break;
}
cout<<"\n\t1.Report card for particular student"
"\n\t2.List all records\n\t3.Exit";
cin>>ch;


}while(ch!='3');
getch();
}

Author : Rounak

Share this

Related Posts